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 November Static Quiz
16th November 2022
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16th November 2022 Static Quiz for UPSC Prelims
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Question 1 of 10
1. Question
2 points
Aruna ranks twelfth in a class of forty – six . What will be her rank from the last?




Correct
Ans : ( c )
Sol : Aruna’s Rank from the last
= 46 – 12
= 34 + 1 = 35
Incorrect
Ans : ( c )
Sol : Aruna’s Rank from the last
= 46 – 12
= 34 + 1 = 35

Question 2 of 10
2. Question
2 points
Ravi is 7 ranks ahead of Sumit in a class of 39. If Sumit’s rank is seventeenth from the last , what is Ravi’s rank from the start?




Correct
Ans : ( d )
Sol : In a class of 39 students , the Sumit position from the first = 39 – 17 = 22 + 1 = 23
The Ravi’s position from the starting = 237
16 + 1 = 17th
Incorrect
Ans : ( d )
Sol : In a class of 39 students , the Sumit position from the first = 39 – 17 = 22 + 1 = 23
The Ravi’s position from the starting = 237
16 + 1 = 17th

Question 3 of 10
3. Question
2 points
In a class of 60 , where girls are twice that of boys , Kamal ranked seventeenth from the top . If there are 9 girls ahead of Kamal , how many boys are after him in rank?




Correct
Ans : ( c )
Sol : In a class of 60 , Number of members after him approximately 45. In this 15 members are boys and 30 members are Girls , According to their positions ratio , after ahead of Kamal 9 girls are there so , 4 members may the boys .
Incorrect
Ans : ( c )
Sol : In a class of 60 , Number of members after him approximately 45. In this 15 members are boys and 30 members are Girls , According to their positions ratio , after ahead of Kamal 9 girls are there so , 4 members may the boys .

Question 4 of 10
4. Question
2 points
Richard is fifteenth from the front in a column of boys . There were thrice as many behind him as there were in front . How many boys are there between Richard and the seventh boy from the end of the column?




Correct
Ans : ( c )
Sol : Number of boys in front of Richard = 14
Number of boys behind Richard = ( 14 x 3 ) = 42
Total number of boys in the column = ( 14 + 1 + 42 ) = 57 .
In a column of 57 boys , the seventh boy from the end is clearly 51 ” from the start , thus , we have to find the number of boys between the 15th and the 51st boy , which is clearly 35 .
Incorrect
Ans : ( c )
Sol : Number of boys in front of Richard = 14
Number of boys behind Richard = ( 14 x 3 ) = 42
Total number of boys in the column = ( 14 + 1 + 42 ) = 57 .
In a column of 57 boys , the seventh boy from the end is clearly 51 ” from the start , thus , we have to find the number of boys between the 15th and the 51st boy , which is clearly 35 .

Question 5 of 10
5. Question
2 points
In a class , among the passed students , Amisha is twenty – second from the top and sajal , who is 5 ranks below Amisha , is thirty – fourth from the bottom . All the students from the class have appeared for the exam . If the ratio of the students who passed in the exam to those who failed is 4 : 1 in that class , how many students are there in the class ?




Correct
Ans : ( b )
Sol : Amisha is 22nd from the top and Sajal is 5 ranks below Amisha , so , Sajal is 27th from the top .
Also , Sajal is 34th from the bottom.
Number of students passed
= 26 + 1 + 33
= 60 .
Let the number of students passed and the numbers failed be 4x and x respectively .
Then , 4x = 60 , x = 15 .
Hence , the number of students in the class
= ( 60 + 15 ) = 75 .
Incorrect
Ans : ( b )
Sol : Amisha is 22nd from the top and Sajal is 5 ranks below Amisha , so , Sajal is 27th from the top .
Also , Sajal is 34th from the bottom.
Number of students passed
= 26 + 1 + 33
= 60 .
Let the number of students passed and the numbers failed be 4x and x respectively .
Then , 4x = 60 , x = 15 .
Hence , the number of students in the class
= ( 60 + 15 ) = 75 .

Question 6 of 10
6. Question
2 points
If the 25th of August in a year is Thursday , the number of Mondays in that month is




Correct
Ans : ( c )
Sol : 25th August is a Thursday .
So , 22nd August is a Monday .
So , Mondays fall on 1st , 8th , 15th , 22nd and 29th of August .
Thus there are five Mondays .
Incorrect
Ans : ( c )
Sol : 25th August is a Thursday .
So , 22nd August is a Monday .
So , Mondays fall on 1st , 8th , 15th , 22nd and 29th of August .
Thus there are five Mondays .

Question 7 of 10
7. Question
2 points
If 1st October is Sunday , then 1st November will be




Correct
Ans : ( c )
Sol : Clearly 1st , 8th , 15th , 22nd and 29th October are Sundays .
So , 31st October is Tuesday.
1st November will be Wednesday .
Incorrect
Ans : ( c )
Sol : Clearly 1st , 8th , 15th , 22nd and 29th October are Sundays .
So , 31st October is Tuesday.
1st November will be Wednesday .

Question 8 of 10
8. Question
2 points
If February 1 , 1996 is Wednesday , what day is March 3 , 1996?




Correct
Ans : ( c )
Sol : 1996 is a leap year and so February has 29 days . Now , 1st , 8th , 15th , 22nd and 29th February are Wednesdays . So , 1 march is Thursday and therefore , 3rd march is Saturday
Incorrect
Ans : ( c )
Sol : 1996 is a leap year and so February has 29 days . Now , 1st , 8th , 15th , 22nd and 29th February are Wednesdays . So , 1 march is Thursday and therefore , 3rd march is Saturday

Question 9 of 10
9. Question
2 points
If the first day of the year ( other than the leap year ) was Friday , then which was the last day of that year?




Correct
Ans : ( b )
Sol : If the year is not a leap year , then the last day of the year is the same as the first day. It is friday .
Incorrect
Ans : ( b )
Sol : If the year is not a leap year , then the last day of the year is the same as the first day. It is friday .

Question 10 of 10
10. Question
2 points
Which two months in a year have the same calendar?




Correct
Ans : ( c )
Sol : Two months will have the same calendar if the period between them is divisible by 7 . Now,
( a ) June + July + Aug + Sep
= 30 +31 +31 +30
= 122
not divisible by 7
( b ) Apr + May + June + July + Aug + Sep + Oct
= 30 +31 +30 +31 +31 +30 +31
= 213
Not divisible by 7.
( c ) Apr + May + June
= 30 +31 + 30 = 19
Divisible by 7.
( d ) Oct Nov = 31 + 30 = 61
( not divisible by 7 )
Incorrect
Ans : ( c )
Sol : Two months will have the same calendar if the period between them is divisible by 7 . Now,
( a ) June + July + Aug + Sep
= 30 +31 +31 +30
= 122
not divisible by 7
( b ) Apr + May + June + July + Aug + Sep + Oct
= 30 +31 +30 +31 +31 +30 +31
= 213
Not divisible by 7.
( c ) Apr + May + June
= 30 +31 + 30 = 19
Divisible by 7.
( d ) Oct Nov = 31 + 30 = 61
( not divisible by 7 )
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